23
54 x 54 x 54 = 147,464
The common factors of 28 and 54 are: 1, 2
68 x 54 = 3672
2x + 33x - 54 35x - 54 We can not find x with the information given. You need to equate somethingto your equation. If your equation equals 0 then... 0=35x-54 35x=54 x=1.543 IF your equation equals x then... x=35x-54 -34x=-54 x=1.588
Assume sum of digits as x+y. It is given x+y=10. Assume those two digit no as 10x+y reverse of it is 10y+x It is given if you reverse it new no will be 54 less than original no So 10y+x=10x+y-54 -9x+9y=-54 -9(x-y)=-54 x-y=6 Equate x+y and x-y x+y-10=x-y-6 x+y-10-x+y+6=0 2y-4=0 y=2 substitute this in x+y =10 x+2=10 x=8 Substitute this x and y in two digit no we assumed that is 10x+y 10*8+2= 82 is original no Reverse of it 28 Ans is 82
28/54 x 100 = 51.851 recurring (that is, 51.851851851...) percent.
28 = 2 x 2 x 7, 54 = 2 x 3 x 3 x 3 so only common factor is 2
Let x = 1st even number. x+2 = 2nd even number. x+ (x+2) = 54; 2x+2 = 54; 2x = 52; x = 26. Therefore x+2 = 28. 26 + 28 = 54.
28 = 2 x 2 x 7 52 = 2 x 2 x 13 54 = 2 x 3 x 3 x 3 ---------------------- The GCF of 28,52,54 is: 2 Note: Since 52 and 54 are only 2 apart, the greatest possible common factor is 2.
The products of 54 (with factors 1 to 12) are as follows:1 x 54 = 542 x 54 = 1083 x 54 = 1624 x 54 = 2165 x 54 = 2706 x 54 = 3247 x 54 = 3788 x 54 = 4329 x 54 = 48610 x 54 = 54011 x 54 = 59412 x 54 = 648
LCM of 28 and 54 is 756.
Algebraically. X = consecutive numbers. X + (X + 1) = 55 2X + 1 = 55 2X = 54 X = 27 =======so, X + 1 = 28 ==== (27, 28) -------------------solution set
9 x 10^14 x 6 x 10^13 x 10^1 = 54 x 10^28 = 5.4 x 10^29 = 54 octillion years
9 x 10^14 x 6 x 10^13 x 10^1 = 54 x 10^28 = 5.4 x 10^29 = 54 octillion years
54 x 54 x 54 = 147,464
54 - 28 = 26
1 x 54 = 54, 2 x 54 = 108, 3 x 54 = 162, 4 x 54 = 216, etc.