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What is the solution of this math ( 54x4 27x3a-16x-8a)?
The question cannot be answered.Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols (plus, minus, times etc). Also, there is no equation in the question so there can be no solution.
Does using your car radio reduce your gas mileage?
Yes. How much depends on the radio. Heres a few examples. 1: Old car, with a radio that only puts out 20x4 watts of power RMS. Not much of a draw on power, so your alternater isnt under much more stress with it. Noticable, probably not. Were talking fractions of miles per gallon 2: My 98 Ford Mustang GT with a mach 460 sound system (Factory) Ok, so the stock radio puts out 54x4 watts of power. Nothing noticable, but then it powers 2 amps, 1 160watt, and one 300 watt for the subs. A bigger difference. I actually notice a difference in gas milage on long trips. About 1 - 2 MPGs. 3: I have a 2010 Ford Fusion that I just put a sound system into. 54x4 watts in the head unit, factory amplified (dont know the specs) and then a 300.1 Kicker amp (rated at up to 600watts). Now, under full load, everything turned up this thing draws alot of power and notice a huge drop in gas milage as well as power. Im talking about 5Mpgs. This is what happens. As the car starts to draw more power, the alternator knows that it needs to apply more friction in order to supply the draw. The alternator gets harder to turn, and the motor has to work that much harder to turn the alternator to supply the power. Therefore you will use more gas with a louder sound system.
What is the meaning of product rule?
The product rule is a formula that is used to find the derivative of the product of two or more functions. It is summarized as thus: y' = u x v' + v x u' ("first times the derivative of the second, plus the second times the derivative of the first"). Ex: y = (2x4 + 6x3 + 9x) X (3x2 + x7+ 12) y' = (2x4 + 6x3 + 9x) X (6x + 7x6) + (3x2 + x7+ 12) X (8x3 + 18x2 + 9) y' = 12x5 + 14x10 + 36x4 + 54x2 + 63x7 + 24x5 + 54x4 + 27x2 + 8x10 + 18x9 + 9x7 + 96x3 + 216x2 + 108 y' = 36x5 + 22x10 + 90x4 + 297x2 + 72x7 + 18x9 + 96x3 + 108
How do you factor 3x to the 6 power plus 54x to the 4 power plus 243x to the second power?
3x5+ 15x3+ 12xAll of these terms have a common factor of 3x, so we can factor it out to get:3x(x4+ 5x2+ 4)Our 'bracketed' term now has the layout of a quadratic equation, except the powers of x have been doubled - x2+ 5x + 4x0(x0= 1, x0*2= x0)This means we can factorise it just like a quadratic, except making sure the x's are squared in the final brackets.x2+ 5x + 4 factorises to (x+1)(x+4), so x4+ 5x2+ 4 will factorise to give (x2+1)(x2+4).Put this all together to get:3x(x2+1)(x2+4)This could be factorised further by treating each of these new bracketed terms as quadratics, but only if complex numbers are allowed - so for simplicity's sake, this is the final product.Otherwise, you could turn it into:3x(x+i)(x-i)(x+2i)(x-2i)
