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Q: What are the first five terms of the sequence with nth term is 7n + 3?

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2,1,0 is th sequence of its terms

37

the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4

9, 17, 25, 33, 41

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The first four terms are 3 9 27 81 and 729 is the 6th term.

5, 8, 11, 14 and 17.

4,8,12,16,20

nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.

91=3n

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I try to be psychic, but fail miserably. If you could give me a clue, like the first few terms of the sequence, I could have a go at giving you the 77th term.

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If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.

1, 16, 81, 256 14641 is the 11th term.

The sum of the terms in a sequence is called a series. Sequence is a function whose domain is the natural numbers. So f(1)= first entry in the sequence, and f(2) is the next.... f(n) is the nth term. We usually don't write sequences that way. Instead of f(1) we write, a1 to refer to the first term. The function tells us the rule we use to find the terms of the sequence. So for example, f says take n and square it. Then the first 3 terms of the sequence are 1, 4 and 9 and the first 3 terms of the series are 1, 5 and 14

If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.

you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given

All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)

It is the description of a rule which describes how the terms of a sequence are defined in terms of their position in the sequence.

5, 11, 17, 23, 29

No, they do not. If the first term is negative, they always decrease.

29

The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r

The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.