56 = 2 x 2 x 2 x 7
56 = 2 x 2 x 2 x 7 OR 23 x 71
You can't. 59 is already prime.
It is: 2*2*2*7 = 56
2 x 2 x 13
As a product of its prime factors in exponents: 22*32*52 = 900
As a product of its prime factors it is: 2*5*5*7*23 = 8050 or as 2*52*7*23 = 8050
As a product of its prime factors: 3*5*5*41 = 3075 or as 3*52*41 = 3075
As a product of its prime factors: 3*5*5*19 = 1425 or as 3*52*19 = 1425
As a product of its prime factors: 2 * 2 * 2 * 5 = 40 As a product of its prime factors: 2 * 2 * 5 * 5 = 100
2 x 2 x 13 = 52
As a product of its prime factors in exponents: 22*3*52 = 300
225 = 32 x 52
2 x 3 x 52
As a product of its prime factors it is: 2*3*5*5 = 150 or as 2*3*52 = 150
32*52 = 225
2 x 2 x 13 = 52
As a product of its prime factors in exponents: 33*52 = 675
75 expressed as a product of its prime factors is 5 squared, and 3.
To find the HCF of two numbers you first need to write them as the product of their prime factors: 52 = 2x2x13 96 = 2x2x2x2x2x3 The next step is to identify any common prime factors. In this case, both numbers have two 2s as prime factors. Multiply these and you get: 2x2 = 4 Thus the HCF of 52 and 96 is 4.
As a product of its prime factors in exponents: 25*3*52 = 2400 Or as 2.4*103 in scientific notation
As a product of its prime factors in exponents it is: 22*3*52*7 = 2100