(5ab)2 = 25a2b2 (provided a and b are elements of a commutative group).
2
The GCF of 5ab and 56b squared is b.
No.
No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab
Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
You add the coefficients, i.e., the numbers. For example, 3ab + 2ab = 5ab.
The GCF of 5ab and 56b squared is b.
35ab squared
35ab squared
No.
(a - 2b)(2a - b)
55/5ab + 4/5ab = 59/5ab
7ab-5ab = 2
gcd of 5ab,28xy
-1ab^2 + 5b + 8 Step-by-step explanation: 3a^2+9ab+5-4a^2-4ab+3 3a^2-4ab^2=-1ab^2 9ab-4ab=5ab 5+3=8 -1ab^2+5ab+8
(5ab^2 + 4cd)(5ab^2 4cd) <
6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab