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Q: What is 6 factorial?

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The value of 9 factorial plus 6 factorial is 363,600

Factorial 6 = 720

144

1.8333

6! + 4! = 720 + 24 = 744

720

3!=6 Answer: 6

10! and 6! means factorial of 10, and factorial of 6, respectively. You can calculate that on most scientific calculators - or you can multiply all numbers from 1 to 6 for the factorial of 6, and all numbers from 1 to 10 for the factorial of 10.

3! = 6

A Factorial (6!= 6x5x4x3x2x1)

Factorial. Normally indicated by "!" eg Factorial 6 would be written 6!

2.5

3! = 3*2*1 = 6

9 factorial = 9! = (9*8*7*6*5*4*3*2*1) = 362880

You get the factorial by multiplying the number with every number before down to 1. Factorial of 3 would be 3! = 3 * 2 * 1 = 6 or the factorial of 5 would be 5! = 5 * 4 * 3 * 2 * 1 = 120.

Do you mean an exclaimation mark (!) An exclamination mark means factorial so............. 3! = 3 factorial 3 factorial means 1x2x3 = 6 2! or 2 factorial means 1x2 = 2 4! or 4 factorial means 1x2x3x4 = 24

dim num as integer, factorial as single num=inputbox("enter a number") factorial = 1 for x = 1 to num factorial = factorial * x next x print"factorial is" ; factorial or By Recursive Method Private Function FindFactorial(number As Integer) If number < 1 Then FindFactorial = 1 Else FindFactorial = number * FindFactorial(number - 1) End If End Function ' recursive is faster and simpler for finding factorial

It can be written in factorial form as 6! Thereafter you can find its value as 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720.

A factorial is a whole number multiplied by all the whole numbers less than that number. So 3 factorial (written as 3!) is 3 times 2 times 1=6

factorial of -1

#include int main() { int fact,Factorial; printf("Please Enter Factorial Number\n"); scanf("%d",&fact); Factorial=func_fact(fact); printf("factorial is %d\n",Factorial); } int func_fact(int number) { int i; int factorial=1; for(i=number;i>=1;i--) { factorial=factorial*i; } return factorial; }

It is 4060.

For any positive integer, n, factorial (n) can be calculated as follows: - if n<2, return 1. - otherwise, return n * factorial (n-1). The algorithm is recursive, where n<2 represents the end-point. Thus for factorial (5) we find the following recursive steps: factorial (5) = 5 * factorial (4) factorial (4) = 4 * factorial (3) factorial (3) = 3 * factorial (2) factorial (2) = 2 * factorial (1) factorial (1) = 1 We've now reached the end-point (1 is less than 2) and the results can now filter back up through the recursions: factorial (2) = 2 * factorial (1) = 2 * 1 = 2 factorial (3) = 3 * factorial (2) = 3 * 2 = 6 factorial (4) = 4 * factorial (3) = 4 * 6 = 24 factorial (5) = 5 * factorial (4) = 5 * 24 = 120 Thus factorial (5) = 120. We can also use a non-recursive algorithm. The factorial of both 0 and 1 is 1 thus we know that the return value will always be at least 1. As such, we can initialise the return value with 1. Then we begin iterations; while 1<n, multiply the return value by n and then subtract 1 from n. We can better represent this algorithm using pseudocode: Function: factorial (n), where n is an integer such that 0<=n. Returns an integer, f. Let f = 1 Repeat while 1<n Let f = f * n Let n = n - 1 End repeat Return f

3! = 3 x 2 x 1 = 6

3! = 3×2×1 = 6