Q: What is 6 minus 1 times 0 plus 2 divided by 2 using PEMDAS?

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Using a word problem using 24 by PEMDAS is simple. You would write 24 times 20 divided 4.

41, if you are using pemdas.

Using PEMDAS, it would go like this: -3x3-9= (-3x3)-9= -9-9= -18. The answer would be -18.

Using pemdas, the subtraction and addition happen at the same time. If there are no parenthesis, then you just go from right to left. 8-5=3 3+4=7 So 7 is your answer.

6 divided by 3 times 25 minus 25 = [(6/3)*25] - 25 using the rules which define the order of operations (BIDMAS/BODMAS or a variant). = [2*25] - 25 = 50 - 25 = 25

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Using a word problem using 24 by PEMDAS is simple. You would write 24 times 20 divided 4.

41, if you are using pemdas.

Using PEMDAS, it would go like this: -3x3-9= (-3x3)-9= -9-9= -18. The answer would be -18.

Using pemdas, the subtraction and addition happen at the same time. If there are no parenthesis, then you just go from right to left. 8-5=3 3+4=7 So 7 is your answer.

The expression “six minus one times zero add two divided by two” can be simplified using the order of operations (PEMDAS). First, we would multiply one by zero, which is zero. Then, we would divide two by two, which equals one. Finally, we would subtract zero from six and add one, resulting in the answer of seven.

SO you would write it out as 4/15-2/9 Using PEMDAS or the order of operations you would divide first so (4/15)-(2/9) which is .266 - .22 (repeating 6 and 2 respectively) which equals .046.

6 divided by 3 times 25 minus 25 = [(6/3)*25] - 25 using the rules which define the order of operations (BIDMAS/BODMAS or a variant). = [2*25] - 25 = 50 - 25 = 25

(36 divided by 6 minus 2) times 3

(4 times 4 factorial + 4) divided by 4 4 factorial + the square root of 4 minus (4 divided by 4)

Using BODMAS:2 × 7 - 32 ÷ 8 = (2 × 7) - (32 ÷ 8) = 10

Using pemdas / gema

22 divided by two is 11, minus 2.