8 + X SQUARED
104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
1
1 squared (1x1) +3=4
The quotient works out as: x^2+2x+4 and there is a remainder of -3
4 + (2/32) + 1
104
3
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
0
7x + 8
x3+3x2+3x+2 divided by x+2 equals x2+x+1
(-2x2 + x + 1) / (x - 1) = (-2x - 1)(x - 1)/(x - 1) = -2x - 1
The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.
Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x ≠0.5
1 squared plus 8 squared or 4 squared plus 7 squared