Study guides

☆☆

Q: What is 80 in the product of its prime factors?

Write your answer...

Submit

Related questions

2x2x2x2x5

The prime factors of 80 are 2,2,2,2,5.The product is 2x2x2x2x5, which is 80.

As a product of its prime factors: 2*2*2*2*5 = 80 As a product of its prime factors: 2*2*5*5 = 100

Prime factorization of 540 = 2x2x3x3x3x5 Prime factorization of 80 = 2x2x2x2x5

2^4 * 5

It is: 2*2*2*2*5 = 80

2*2*2*2*5

The prime factors of 80 are: 2 and 5.

The prime factors of 80 are: 2 and 5The only prime number that goes into 80 is 2.

The product of factors is called the product.The product of prime factors is called the prime factorization.

Multiply prime numbers or prime factors to find their product.

The product of the prime factors of 42 is 42.

2 x 2 x 2 x 2 x 5 = 80

2 x 2 x 2 x 2 x 5 = 80

The prime factors of 18 are 2, 3, and 3. The product of these prime factors is 18.The distinct prime factors of 18 are 2 and 3. The product of these distinct prime factors is 6.

37 is already prime. There is no product of prime factors for prime numbers.

The product of the prime factors of 235 is 235. The product of the (not necessarily distinct) prime factors of any number is that number.

The prime factorization of a number is writing it as a product of its prime factors.

The prime factors of 80 are 2 and 5. For them to be common, they need to be compared to another set of prime factors.

The product of the prime factors of a number is the number itself.

As a product of its prime factors: 225*5 = 100

The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.

The prime factorization of a number is writing it as a product of its prime factors.

Two of the factors of 80 are prime numbers: 2 and 5.

215 as the product of prime factors can be represented as 215 = 5x43