9 is only dividable by 1,3, and9
25 is only dividable by 1,5and 25
so 1
is 567 divisible by both 2 and 9
Yes because you can divide it by 9 and get 25.
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
Both.
Every number is divisible by any non-zero number. 1485 is not evenly divisible by both of them.
9, yes. 25, no.
No, it is not... For any number to be divisible by 9, the sum of its digits must ALSO divide by 9. In this case, 8+9+4+4=25... 25 is not divisible by 9 !
No, it is not.
9 is divisible by both 3 and 9
Yes, 9/25 can be simplified. Both 9 and 25 share a common factor of 1, so there are no other numbers that can divide evenly into both. Therefore, 9/25 is already in simplest form.
is 567 divisible by both 2 and 9
1
5
not both 10 yes 25 no if divisible exactly by 25 a number ends in 25 50 75 00
Yes because you can divide it by 9 and get 25.
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.
It's divisible by both (240 times for 9, 270 times for 8)