Q: How many ways can you stack 77 books in a pile?

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i think about 5929 ways

5.This question is the same as asking how many factors does 18 have.18 has the following factors:1, 18, 2, 9, 3 & 6.Therefore you could pile the books 6 different ways.However, as the question says equal piles (plural) then I think we should probably discount 1 pile of 18 books, so the answer is 5.

Use the factors of the number. Factors of 10 are... 1,2,5 & 10. Therefore they will stack either in 1 row of 10 books or 2 rows of 5.

10!/5!x5! 3,628,800/14,400 252. There are 252 ways.

A deck can be divided into 3 piles with different numbers in each pile in 225 ways. This answer does not consider which cards are in which pile - only the number of cards in each pile.A deck can be divided into 3 piles with different numbers in each pile in 225 ways. This answer does not consider which cards are in which pile - only the number of cards in each pile.A deck can be divided into 3 piles with different numbers in each pile in 225 ways. This answer does not consider which cards are in which pile - only the number of cards in each pile.A deck can be divided into 3 piles with different numbers in each pile in 225 ways. This answer does not consider which cards are in which pile - only the number of cards in each pile.

You can get a picnic basket and stack them up in there. Another trick is to stack them on a bookshelf if you have one. Simply place them between two hard books to keep them upright.

240. 120 ways with the books stacked verticly, and 120 ways with the books stacked horizontaly, or one on top of the other.

35

93

24 ways

210 ways.

6x5x4x3x2x1 ways, or 6! ways, or 740 ways.

Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.

(5x4x3)/(3x2x1) = 10

There are 2*5! = 240 ways.

6 ways

The answer depends on how many books on each subject there are.

30 ways.

zero its impossible

81

You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.

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12!/(5!*7!)The number of ways to arrange nitems is n!, where "!" is the factorial function. The number of ways we can arrange the 12 books is therefore 12!. However, we don't really care what order the first 5 books are in, or what order the last 7 books are in, as long as they're the same books. We therefore divide by the number of ways to arrange 5 books and the number of ways to arrange 7 books.

I have heard you can place a pile of books on the floor and jump knee high over them, like 100 times or something.

there are 220 combinations of arranging 12 books chosing 3

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