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Q: What sum of two number is 66 and their difference is 8?

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66 is a single number and so there is no sum as such. The only value is 66.

There isn't one. The only two digit numbers whose sum of digits is 12 are: 39, 48, 57, 66. (I didn't include 75, 84, or 93 since interchanging their digits and subtracting from the original number will be a negative result.) None of the four remaining numbers will exceed the original by 25. 66 won't work since the difference will be zero. Using 39, the new number (93) will exceed the original by 54; using 48 the difference will be 36; and using 57 the difference will be 18

It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.

The numbers 100 and 66, since 100+66=166 and 100-66=34.

The numbers are 24 and 66.

They are: 61+67 = 128 or if you mean 29+37 = 66

The number is 55+66 = 121

66

There is no product of prime numbers building 66. The sum of prime number is doing it: 13 +53 = 66

The numbers are 65 and 66.

66.

11 and 66.

83

-66 and -68

(21 + 45) / (63 - 52) = 66 / 11 = 6

66 + 17 = 83

a + b = 50 a - b = 16 2a = 66 a = 33 b = 17

20 and 46

66

If you add an even number with another even number, you will always get the sum as an even number. Ex: 22 + 44 = 66

x+(x+2)= 66.

The four consecutive integers with the sum of -66 are -18, -17, -16 and -15.

66>> 6+6=12

The sum is 28+38 = 66

11 and 6 11+6 = 17 11*6 = 66