AC=5
AB=8
A=1
B=8
C=5
BC=40
If those are the legs, the hypotenuse is √113
AB = 2 x 4 (8) C = 3 D = 5
Using the distance formula the length of ab is 5 units
ab = 8-cDivide both sides by ba = (8-c)/b
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If these are sides of a triangle then AC can have any value in the interval (3, 13).
ac is 7 if b is 3 and a is 2 a nd c is 5
36
If it's a right angle triangle then side ac is 10 units in length.
If those are the legs, the hypotenuse is √113
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
28
Depends which angle is right... If it's angle acb then ab = sqrt(225 + 289) ie 22.67; if it's angle bac then ab = sqrt(289 - 225) ie 8, which seems the more likely.
10
It states that (ab)c = a(bc).
Note!!!! ignore the S at the end these are the questions 1. side AC= 31 cm, side BC= 20 cm and angle B= 58 degrees 2. side AC= 21 cm, side BC= 28 cm and side AB= 32 cm 3. side AC= 8 cm and side AB= 10 cm please help last 3 questions of my homework. My teacher collects it =(
6