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3X2 + 6X + 9
3(X2 + 2 + 3)
-----------------------3 is a common factor of all terms
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∙ 12y ago
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How do you factor 6x - 6x -16?
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
What is the factored form of 3x2 plus 6x-24?
3x2 + 6x - 24First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,3x2 + 6x - 24 = 3(x2 + 2x - 8)Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:(x + ??)(x + ??)Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,(x2 + 2x - 8) = (x - 2)(x + 4)So,3x2 + 6x - 24 = 3(x - 2)(x + 4)
Factor X2 plus 6X plus 4?
Not factorable
What is the factor 48x plus 8?
8(6x+1)
Factor x cubed plus 5x squared plus 6x?
x(x2+5x+6)
One factor of 3x2- 6x plus 9 is?
Just looking at it, one factor is 3.
What is the common factor of 3X2 plus 6X?
3x2 + 6x is ONE expression. A common factor is a factor that is COMMON to two (or more) expressions - not just one. An alternative answer: 3x can be factored out of both of those.
What is One fatcor of 3x2-6x plus 9 equals?
One factor is 3.
How would you factor factor factor 18x to the 3-6x to the 2 plus 24x?
6x(3x2 - x + 4)
Factor of 3x2- 6x plus 9 is?
3(x2 - 2x + 3)
Factor x3 plus 3x2-6x-8?
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
How do you factor -6x plus 9x2-24?
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
How do you factor 6x - 6x -16?
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
Factor this polynomial completely 3x2 plus 2x - 8?
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
What is 3x squared plus 6x-3 equals 8 in the form of Ax squared plus Bx plus C equals 0?
It is: 3x2+6x-11 = 0
What is the answer to this equation 3x2 plus 6x plus 24 equals 0?
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
36x2 plus 60x plus 25 factor completely?
(6x + 5)(6x + 5) or (6x + 5)2
