f(n) = n^3 + 4n + 2 = prime
This works for at least two numbers
f(0) = 2
f(1) = 7
Yes, some times it does and and other times it does not.
It is the cube of a prime number.
No.
If a factor appears 3 times, you get this factor (only once) times the cube root of a smaller number (the original number divided by the factor cubed).
The cube root of this number is 1 more than the smallest prime?
The number 27 has a cube root of 3, which is 2 (the smallest prime) plus 1.
don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
37 is not a cube number but it is a prime number because it has only two factors which are itself and one
A fair cube 60 times.
No, being a perfect cube would mean it has factors.
The cube root of this number is one more than the smallest prime
343 is the palindromic and cube number.7*7*7=3437 is being times three times by itself to get this palindromic and cube number.Also 1331 is a palindromic and cube number.11*11*11=133111 is being times three times by itself to get this palindromic and cube number.