Apply Pythagoras
h^2 = l^2 + s^2
h = 25
l = s + 17
Substitute
25^2 = s^2 + ( s + 17)^2
625 = s^2 + s^2 + 34s + 289
Equating to zero
2s^2 + 34s - 336 =0
Divide by '2'
s^2 + 17s - 168 =0
Factor
( s + 24)(s - 7) = 0
Hence s = 7 (& s = -24 is unresolved).
If the hypotenuse is 25 cm
Then the shorter leg is 7 cm
Using Pythagoras' theorem: (17+7)2+72 = 625 and its square root is 25 cm
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
If you have the shorter legs length, then for the hypotenuse, just multiply the shorter leg by 2. For the longer leg, multiply the shorter leg by the square root of 3.
There are an infinite number of different sets of lengths that will do it. You have to start by choosing the length of one side, and when you do that, here's how to find the others: Shorter leg = (longer leg) x 0.364 Shorter leg = (hypotenuse) x 0.342 Longer leg = (shorter leg) x 2.747 Longer leg = (hypotenuse) x 0.94 Hypotenuse = (shorter leg) / 0.342 Hypotenuse = (longer leg) / 0.94
The shorter leg is 1/2 of the hypotenuse, while the longer leg is (sin60°) times the hypotenuse or about 0.866 times as long. (7.8/0.866) gives the hypotenuse as 9.0 and 9.0/2 = about 4.5 unitsor use the tangent ratio:7.8/tan 60° = 4.5033321 or about 4.5 in length
Use the rule that the shortest leg has length p, the other leg has length 2p and the hypotenuse has length p*sqrt(3) Where sqrt(number) if the square root of the number.
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
If you have the shorter legs length, then for the hypotenuse, just multiply the shorter leg by 2. For the longer leg, multiply the shorter leg by the square root of 3.
If it is a 45-45-90 triangle, then divide the hypotenuse by the square root of 2. If it is a 30-60-90 triangle, then the shorter leg would be the hypotenuse divided by 2. And the longer leg would be the the shorter leg multiplied by the square root of 3.
Subtract the squared longer leg's squared length from the hypotenuse's square to obtain the squared shorter leg length. Then find the square root of that answer for your final answer. In other words: 53 squared minus 45 squared equals your squared answer.
The shorter leg is 6 feet long
The shorter leg is 9 feet long
There are an infinite number of different sets of lengths that will do it. You have to start by choosing the length of one side, and when you do that, here's how to find the others: Shorter leg = (longer leg) x 0.364 Shorter leg = (hypotenuse) x 0.342 Longer leg = (shorter leg) x 2.747 Longer leg = (hypotenuse) x 0.94 Hypotenuse = (shorter leg) / 0.342 Hypotenuse = (longer leg) / 0.94
The shorter leg is 1/2 of the hypotenuse, while the longer leg is (sin60°) times the hypotenuse or about 0.866 times as long. (7.8/0.866) gives the hypotenuse as 9.0 and 9.0/2 = about 4.5 unitsor use the tangent ratio:7.8/tan 60° = 4.5033321 or about 4.5 in length
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Use the rule that the shortest leg has length p, the other leg has length 2p and the hypotenuse has length p*sqrt(3) Where sqrt(number) if the square root of the number.
Short leg is 6 feet.
.The hypotenuse is twice as long as the shorter leg The longer leg is twice as long as the shorter leg.