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How many bit strings of length 8 ends with a 0?
Half of them.
How many bit strings are there of length eight?
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
Perimeter of a rectangle is 40 ft The width is 8 feet less find the length?
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
What is the length of image if the scale factor is 8 and the length of figure is 10yds?
Length of image = Length of original*Scale factor = 10*8 = 80 yards.
How many bit strings of length 10 have?
1024
How many bit strings of length 8 are there which begin with a 0 and end with a 0?
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
How many bit strings of length 8 ends with a 0?
Half of them.
What is a 8 pattern of 8 bits?
A bit is an on/off switch. There are 8 bits in one byte.
How many bit string of length 8 contain exactly there 1's?
56
According to word size how many instruction in 8085?
The 8085 is an 8 bit processor, so its word length is 8 bits.
How many bit strings of length 8 contain exactly three 1's?
56 The number of triples of 1s on 8 bits
What is UTF-8 and UTF-16?
UTF-8 is a variable length character encoding method for Unicode.. It is otherwise known as 8-bit UCS/Unicode Transformation Format. UTF-16 is another variable length character encoding method for Unicode, that is a stronger then UTF-8. It is otherwise known as 16 bit Unicode Transformation Method.
What is 12 in binary form?
for a four bit pattern, its 1100....8 bits 00001100
Does the number 174 appear in the pattern 8?
The answer depends on details of pattern 8. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.
What is maximum length of variable in c?
The maximum length of a variable is dependent on the platform. In a 32 bit platform, this might be 4 bytes, although the compiler and run-time library might support 64 bit, or 8 byte variables. In a 64 bit platform, the length might be 8 bytes.(Arrays, strings, structures, classes, etc. are aggregated types, not scalar types, so they don't count in this answer.)
Why the computer start with 8 bit?
It didn't, early computers had a very wide range of word and character sizes many machines were decimal so their word/character sizes were defined in decimal digits not binary bits. Even microprocessors the first commercial microprocessor the Intel 4004 was a 4 bit not 8 bit machine. The 8 bit byte as a standard only originated in 1964 with the IBM System/360.Some examples of different computers of the past:ABC: 50 bit binary words; no characters.ENIAC: 10 digit decimal words; no characters.IAS: 40 bit binary words; no characters.UNIVAC 1: 12 character/digit decimal words; 1 digit characters.IBM 701: 36/18 bit binary words; 6 bit characters.IBM 702: variable length character/digit words; 1 digit (6 bit) characters.UNIVAC 1101: 36 bit binary words; 6 bit characters.IBM 650: 10 digit decimal words; 2 digit characters.IBM 704: 36 bit binary words; 6 bit characters.UNIVAC 1103: 36 bit binary words; 6 bit characters.IBM 705: variable length character/digit words; 1 digit (6 bit) characters.IBM 709: 36 bit binary words; 6 bit characters.IBM 7090: 36 bit binary words; 6 bit characters.IBM 1620: variable length decimal words; 2 digit characters.IBM 1401: variable length character/digit words; 1 digit (6 bit) characters.DEC PDP-1: 18 bit binary words; 6 bit characters.IBM 7030: 64 bit binary words, variable length character/byte strings; variable length (4 to 8 bits) characters/bytes.CDC 6600: 60 bit binary words; 6 bit characters.DEC PDP-8: 12 bit binary words; 6 or 8 bit characters.IBM System/360: 32 bit binary words, variable (up to 32 digits) length decimal words; 8 bit characters/bytes.DEC PDP-10: 36 bit binary words; variable length (1 to 36 bits) characters.UNIVAC 1110: 36 bit binary words; 6 or 9 bit characters/bytes.etc.
How many bit strings are there of length eight?
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
