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A maximum or a minimum - collectively known as an extremum.

Q: What is a data point that is located away from most other points?

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Do you mean "Between two other points? If yes, when it lies on a straight line between both points that are farther away and on the same line.

If it lies on the trend line of the other points then it has no particular name. Otherwise, it may be called an outlier.

A triangle in which a point has been selected on each side (away from the eds) and these points are joined together (in pairs) by straight lines.

This is sometimes referred to as center of mass, as well. If you could take the vector sum of all the torques produced by all of the 'point-masses' to this particular point they will net to zero. For simplicity, consider a weightless see-saw. On the right side of the see-saw is a person weighing 100 pounds, who is 6 feet away from the pivot point. This produces (100 pounds force) x (6 feet ) = 600 foot-pounds force of torque, in the clockwise direction. On the other side of the see saw is a 200 pound person at 3 feet away from the pivot. This will produce (200 pounds force) x (3 feet ) = 600 foot-pounds force of torque, in the counter-clockwise direction. So the see-saw is balanced. Now for each 'point-mass' (this is an infintessimaly small area with an associated small mass), a certain distance away from the centroid, there would be an equal mass the same distance away on the other side, but a vertex is farther away than the opposite side, so there will be two points, each at an angle from the centroid to a point which are a shorter distance, but add to balance the farther points. This is kind-of hard to explain without pictures.

The set of points 26.5 units away from the point (2, 6) are those points that lie on the circle with centre (2, 6) and radius 26.5; this has equation:(x - 2)² + (y - 6)² = 26.5²The set of points 26.5 units away from the line y = 2 are those points which lie on the lines which are parallel to 26.5 and 2 units away, ie the lines y = 2 ± 26.5→y = -24.5 or y = 28.5The points where these lines meet the circle are the required points.By substituting the y values of the two lines into the equation for the circle and solving it will give you the required points.That's HOW to find all the points.------------------------------------------------------------------------------------------------Solving the problem and finding the points:line y = -24.5(x - 2)² +(-24.5 - 6)² = 26.5² → x² - 4x + 4 + 30.5² - 26.5² = 0→ x² - 4x + 232 = 0→ x = 2(1 ± √-57)As the square root is of a negative number the line does not meet the circle - it has no points in commonline y = 28.5(x - 2)² +(28.5 - 6)² = 26.5² → x² - 4x + 4 + 22.5² - 26.5² = 0→ x² - 4x - 192 = 0→ (x + 12)(x - 16) = 0→ x = -12 or 16→ points are (-12, 28.5) and (16, 28.5)→ all the points that are 26.5 units away from the point (2, 6) and the line y = 2 are (-12, 28.5) and (16, 28.5).

Related questions

Do you mean "Between two other points? If yes, when it lies on a straight line between both points that are farther away and on the same line.

If it lies on the trend line of the other points then it has no particular name. Otherwise, it may be called an outlier.

Then one point is 20 units away from the other.

If the given point charge is of positive one then the field points away from the charge. This is because we define the field at a point as the FORCE acting on unit POSITIVE charge. Like charges have to repel and hence the direction. If, other wise, the point charge is negative then electric field due to this negative charge would be towards the negative and not away from it.

It points away from the Sun

A locus of points is just the set of points satisfying a given condition. The locus of points equidistant from a point is a circle, since a circle is just a set of points which are all the same distance away from the center

A comet's tail points away from the sun

Far away shots? There are only three different number of points allocated in baskeball. A foul shot gets you one point. a basket anywhere within the three point like gets you two points. And anything beyond that whether it is half court or just behind the three point line, you get three points

None of them.

All comet tails point away from the Sun.

No. As of now, you can neither lose trust points, nor take them away from another user.Trust points cannot be deleted by anyone; once a trust point is given, it cannot be taken away.

If you point the north side of the compass away from you the compass will point south. Because the needle always points north (magnetism).