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What is a number n where if the sum of the digits of the number is divisible by n then the number itself is divisible by n?
Wiki User
∙ 10y ago
That works with 3 and 9.
Wiki User
∙ 10y ago
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The factor of every palindrome with an even number of digits?
Every palindrome with an even number of digits is divisible by 11. The easiest way to see this is to recall the divisibility rule by 11: if a number X is written as ABCDEFG... (here A,B,C, ... are digits), then it's divisible by 11 if and only if the sum A-B+C-D+E-F+G-... is divisible by 11. In a palindrome with an even number of digits, each digit will appear in an odd position and in an even position, so when we calculate this sum, it will be added once and subtracted once, canceling. Since all the digits cancel, the sum A-B+C-D+... will be 0, which is divisible by 11. So the original number ABCD....DCBA was also divisible by 11.
How do know a number is divisible by six?
It's very easy to test a number to see if it is divisible by 4 or by 9. If it passes both tests, then it is divisible by 4x9=36.To test for divisibility by 9, add the digits of the number. If the sum is divisible by 9, then the number is divisible by 9.To test for divisibility by 4, look at the last two digits. If they are a multiple of 4, then the number is divisible by 4.
Is 3300 divisible by 3?
No, 8303 is not divisible by 3. 2767 as quotient and 2 as remainder is obtained: 8303 = 3 x 2767 + 2 A quicker way to check without doing the actual division is by adding all the digits of number and then check if the sum is divisible by 3. If the sum is divisible then the number is also divisible. In this case sum of digits = 8 + 3 + 0 + 3 = 14 14(sum) is not divisible by 3 so 8303 is not divisible by 3.
How do you use divisibility rules to find at least for factors of a number?
Take the number 3336. You know it's divisible by 1 because everything is. You know it's divisible by 2 because it's even. You know it's divisible by 3 because the digits add up to a multiple of 3 and you know it's divisible by 4 because the last two digits are divisible by 4. So you've found at least four factors: 1,2,3 and 4.
What are the divisible by 3?
If, when divided by 3, it leaves no remainder. Also, if you add the individual numbers up and that number is divisible by three, the larger one is as well. Example: 12345 adds up to 15. 15 is divisible by three. So is 12345.
If the sum of the digit is divisible by 3 the number is divisible by?
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
What is a number n where if the sum of the digits of the number is divisible by n, then the number itself is divisible by n?
(The assumes that "the number" in the question is not n, although if they are they same number, this is still true.) "If the sum of the digits of the number is divisible by n, then the number itself is divisible by n" is true if n is 3 or if n is 9.
A number n where if the sum of the digits of the number is divisible by n then then the number itself is divisible by n?
This works with 3, and with 9.
A number is divisible by 3 if the blank is divisible by 3?
A number is divisible by 3 if the sum of its digits is divisible by 3.
A number n where if the sum of the digits of the number is divisible by n then the number itself is divisible by n?
n = 1, 3 or 9.
Indentify the conclusion what conditional a number is divisible by 3 if the sum of the digits of the number is divisible by 3?
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
Is 1 trillion 17 a prime number?
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
Is 345456543 a prime number?
No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.
Is 531 a prime number?
No. The sum of its digits, 5 + 3 + 1, is divisible by 3, which means the number itself is also divisible by 3.
Is 182763 divisible by 9?
The sum of the digits is 27, which is divisible by 9, so the number itself is divisible by 9. When divided by 9, it equals 20307.
If the sum of the digits is divisible by 3 the number is divisible by what?
9
If the sum of the digits is divisible by 3 the number is divisible by?
9
