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cos2x + 2sinx - 2 = 0

(1-2sin2x)+2sinx-2=0

-(2sin2x-2sinx+1)=0

-2sinx(sinx+1)=0

-2sinx=0 , sinx+1=0

sinx=0 , sinx=1

x= 0(pi) , pi/2 , pi

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โˆ™ 2011-04-27 21:54:46
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Q: What is a numerical value for x if cos2x plus 2sinx-2 equals 0?
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