Q: What is a profit of 27 using integers?

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The integers are 26, 27 and 28. Using just oddconsecutive integers you have 25, 27 and 29.

The integers are 26 and 27.

7 + 9 + 11 = 27

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The integers are -11, -9 and -7.

7 23 + 25 + 27 = 75. The largest of these 3 integers is 27.

27 is an integer and integers cannot be simplified.

They are consecutive odd integers: 25 and 27.

25, 26 and 27.

The three integers are 25, 26, and 27.

The greatest factors of any positive integers re the integers themselves. The GCF of 27 and 36 is 9.

You said between, that means not including either 27 or 42. So 'between' 27 and 29, there is one integer(28). 29-27 = 2, which is one more than the # of integers between. So subtract (42-27) and that will be one more than the integers between.

The integers are 27, 28, 29 and 30.

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27 and 81; 27 + 81 = 108, and 3 x 27 = 81

The integers are 26, 27, 28 and 29.

The three integers are -27, -26 and -25.

27 + 28 + 29 + 30 = 114

The two consecutive integers that have a sum of 53 are 26 and 27.

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-10, -9, and -8

They are: 7+9+11 = 27

Try squaring different integers (hint: in this case, the integers will be fairly small). If you find that the square of one integer is less than 27, and the square of the next integer is more than 27, you have your answer.

They are odd consecutive integers: 21, 23, 25 and 27.

7 + 9 + 11 = 27

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