Best Answer

It could be 27 because 3*3*3 = 27

Q: What is a rational number whose cube root is a whole numbers?

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If the square root is a whole number, then the square of the square root, the original number, is also a whole number; all whole numbers can be expressed as themselves over 1, and so are rational numbers. The answer is thus any square number, ie the square of the natural numbers: 1 (1²), 4 (2²), 9 (3²), 16 (4²), etc.

-27 is one possible answer.

27 is a perfect cube.

That's a perfect cube.

It is a real rational negative integer number whose value is -3

Related questions

How about 27 whose cube root is 3 which is a rational whole number.

Rational numbers whose square roots are whole numbers are themselves whole numbers. They are called square numbers, e.g. 1, 4, 9, 16, 25 and so on.

They are perfect squares.

The product will be a rational number whose absolute value is bigger than the absolute value of the whole number.The product will be a rational number whose absolute value is bigger than the absolute value of the whole number.The product will be a rational number whose absolute value is bigger than the absolute value of the whole number.The product will be a rational number whose absolute value is bigger than the absolute value of the whole number.

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If the square root is a whole number, then the square of the square root, the original number, is also a whole number; all whole numbers can be expressed as themselves over 1, and so are rational numbers. The answer is thus any square number, ie the square of the natural numbers: 1 (1²), 4 (2²), 9 (3²), 16 (4²), etc.

It's rational. It can be written as the quotient of two numbers whose HCF is one.

A perfect square.

a perfect cube

27 is a perfect cube.

-27 is one possible answer.

They are all non-positive rational numbers.