Wiki User
∙ 12y agono
Wiki User
∙ 12y agoA juice box has a length of 3 inches, width of 1 inch and height of 4 inches. What is the total outside surface area of the juice box? Also how many cubic inches of juice can it contain if the wall thickness of the box is negligible and juice is filled only to 7/8 of the height?
To obtain the ratio of surface area to volume, divide the surface area by the volume.
surface area/ volume. wider range of surface area to volume is better for cells.
A triangle is a flat area, therefore it has a surface area, not a volume. Density is unrelated to the problem; you would need some additional information to calculate the surface area.
Volume=area * length of that surface
A juice box has a length of 3 inches, width of 1 inch and height of 4 inches. What is the total outside surface area of the juice box? Also how many cubic inches of juice can it contain if the wall thickness of the box is negligible and juice is filled only to 7/8 of the height?
it's the problem of surface area -to- volume ratio that mean there is no fitting between increasing of surface area and increasing of volume
To obtain the ratio of surface area to volume, divide the surface area by the volume.
The surface-area-to-volume ratio may be calculated as follows: -- Find the surface area of the shape. -- Find the volume of the shape. -- Divide the surface area by the volume. The quotient is the surface-area-to-volume ratio.
surface area/ volume. wider range of surface area to volume is better for cells.
A triangle is a flat area, therefore it has a surface area, not a volume. Density is unrelated to the problem; you would need some additional information to calculate the surface area.
cell division
Volume does not, surface area does.
Volume=area * length of that surface
surface area divided by volume
surface area/ volume. wider range of surface area to volume is better for cells.
Well, first of all, that's no sphere.-- A sphere with surface area = 300 has volume = 488.6.-- A sphere needs surface area of 304.6 in order to have volume = 500.But this is just a ratio exercise, not a geometry problem, so we'll just use the numbersgiven in the question. It's just some sort of wacky humongous paramecium:Surface area = 300Volume = 500Ratio of (surface area)/(volume) = 300/500 = 0.6 .