The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
Sum the digits in the odd positions in the integer. Sum = XSum the digits in the even positions in the integer. Sum = YIf X - Y is a multiple (including negative or 0), then the given integer is divisible by 11.
The only stable pattern is that the difference between the sum of all the digits in odd locations and the sum of all digits in even locations is a multiple of 11.For example, 5678*11 = 62458Sum of odd locations = 6 + 4 + 8 = 18Sum of even locations = 2 + 5 = 7Difference = 18 - 7 = 11 which is a multiple of 11.
The difference betweenthe sum of the digits in odd positions andthe sum of the digits in even positionsis divisible by 11.
You need to add all the digits at odd positions, and subtract all the digits at even positions (counting positions from the right). For example, for the number 143, you calculate: +3 + 1 - 4 = 0.If you get a multiple of 11 (including 0), as in the example above, you have a multiple of 11.
22, 2+2= 4 and half of 22 is 11 which is odd