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Q: What is b squared plus ab minus two minus two b squared plus two ab?

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C minus B equals AB

No. The child could be either AA or Ao and they would have plus or minus, depending on if the a plus parent has plus plus, or plus minus

Let y= ab+(- a)(b) +(-a)(-b) factor out -a y= ab+(-a){b+(-b)} y=ab+(-a)(0) y =ab -------------------(1) now factor out b y= b{a+(-a)}+(-a)(-b) y= b(0) +(-a)(-b) y= (-a)(-b)-----------------(2) equate (1) and (2) (-a)(-b)=ab minus x minus = positive

x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)

No, AB+ people can receive blood from all blood groups.

This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)

ab(ab) =2ab

4

If you have two straight lines AB and BC such that the two lines meet at B and AB and BC make 90 degrees with each other then the pythagorean theory (theoram) states that the length of line AC (assume that points A and C are joined by a straight line) then (AC) squared = (AB) squared +(BC) squared

No. O is recessive to all other blood types. So if you're O you can't carry A or B. An AB child needs each parent to be carrying either A or B. Therefore two O parents cannot have an AB child.

That factors to (a + 1)(a + b) a = -1, -b b = -a

ab=1a+1b a is equal to either 0 or two, and b is equal to a

No, a Type AB blood donor could not give to a Type O recipient. The A & B refer to antigens, or proteins, on the surface of the red blood cells. Type O people have neither A nor B antigens, thus, their body rejects the donor blood, which has both A and B antigens. Here is a chart: Type Given Can Receive: O O, A, B, AB A A, AB B B, AB AB AB This is not exactly correct, but for the intents of your question, it should serve. The exact blood types would be O, A plus, A minus, B plus, B minus, AB plus, and AB minus.

Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)

The problem here is nobody knows if "ay squared" is (ay)2 or ay2 etc. To solve a mathematical problem it must be set out mathematically or nobody knows your intention. Here is a sort of mathematical statement which is unclear, and although it ends in a question mark, nobody knows what the question is, even if you do. Try again and people will do their best to answer it. I read the question as: x2y2 + ay2 + ab + bx2 ? But what is required to be done with it?

No , a mom with o plus will have a o plus child only. If the child is ab plus then mom will also be ab plus

A^2-2ab+B^2 is actually (A+B)^2 AB squared is A^2B^2 or (AB)^2

yes, because the offspring could take AB or just B or even BB .

yes because ab plus bc is ac

Two negatives make a positive so your equation simplifies firstly as 4ab + 3ab and finally as 7ab.

yeah the child can be A+, B+ or AB+