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Q: Is the reciprocal of an integer always less than the integer?

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When a number is a fraction, the reciprocal will always be greater than the original number. When the original number is a whole number, the reciprocal will be a fraction, which is less than a whole number.

A mixed number must have an integer part (and a fractional part). Consequently, a mixed number must be greater than one. The reciprocal of a number greater than one is less than one (and conversely) since the two, when multiplied together, make 1.

??? explain better.

Always

That's always the case.

Its reciprocal is either less than 0 or greater than 1.

Negative 14 is less than 14 because a positive integer is always greater than a negative integer. EX: -16 is less than 1

less than

The above statement is not true!-3/4 is a fraction which is less than 1. Its reciprocal is -4/3 which is also less than 1, NOT greater.

The integer "-8" is less than "-7".

An integer is a whole number, and the largest integer less than 9.5 would be 9.4

By definition, a negative integer is any integer less than zero. Similarly, a positive integer is any integer greater than zero. It should be immediately obvious that an integer cannot be both less than and greater than zero. Therefore, a negative integer cannot be greater than a positive integer.

It depends, if a number with positive integers is greater than the number with the negative integer therefore the sum will be in positive integer. And if the number with positive integer is less than the number with the number with negative integer then the sum will be in negative integer.

Subtract any POSITIVE integer from -2, and you get an integer that is smaller.

Not always because it could be less than 0 as for example -3 because an integer is a whole number without decimals or fractions

2

Yes.

Reciprocal of any non - zero number [other than 1 (because reciprocal of 1 is 1)]is always less than '1' .============================The first contributor disputes the change:Sorry, Anu. What about the non-zero number 0.5, whose reciprocal is 2 ? ? ?

1

This is a clever question. I would say: "Always". To be more precise: The product is never greater than either factor, and if neither factor is ' 1 ', then the product is always less than both.

It can be greater than, equal or less than the original integer. There are three possible values for the second integer: It is positive, in which case the result will be less than the original integer, eg 5 - 2 = 3 and 3 < 5;It is zero, in which case the result will be the same as the original integer, eg 5 - 0 = 5 and 5 = 5;It is negative, in which case the result will be greater than the original integer, eg 5 - -2 = 7 and 7 > 5.

yes it is

There are no positive integers less than any negative ones.

One is an integer, it is equal to one and less than two.