int x = 2 * (a + b);
a2+2ab+b2+2ac+2bc+c2+2ad+2ae+2bd+2be+2cd+2ce+d2+2de+e2
{ int a,b; { a=a^2; } { b=b^2; } { c=a^2+b^2+2*a*b; print f("%d%d%d",&c); get ch(); } ]
Roughly speaking, to get a unique solution - or at least, a limited number of solutions - if you have 3 variables, you need 3 equations, not just 2. With the two equations, you can get a relationship between the three variables, but not a unique value for a, b, and c. To get the general relationship, solve both equations for "c", replace one in the other, and solve the resulting equation for "a" to get the relationship between the variables "a" and "b". Then, for any valid combination of values for "a" and "b", use the simpler of the original equations (a + b + c = 24) to get the corresponding value for "c".
You write it exactly the same as you would write it in any other verions of C++, by taking user input to determine the three sides of your triangle. In other words, input three real numbers. What you do with those three numbers is entirely up to you, but presumably you'd want to calculate the angles of a triangle given the length of its three sides. For that you would need to use the cosine rule which states that for any triangle with angles A, B and C whose opposing sides are a, b and c respectively, cos A = (b2 + c2 - a2)/2bc and cos B = (c2 + a2 - b2)/2ca. Knowing two angles, A and B, you can easily work out that angle C must be 180 - (A + B).
This is better explained through a wiring diagram. AC 3 phase motor has three windings. Each winding has two terminals. Lets us denote each winding as follows. Winding 1 - A1 and A2, Winding 2 - B1 and B2. Winding 3 - C1 and C2. Main incoming supply, 3 phases, are denoted by R, Y and B. Connect R to A1, Y to B1, B to C1. Connect A2,B2 and C2 to a common point (neutral). I strongly suggest to refer to motor name plate, its wiring diagram. You need to also check the direction of rotation.
a2+2a2b+2ab2+b2
a2
a2 - 4a + 4
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
l a2 b2 is c2!!Its completely norma
sqrt(a2 + b2) can't be simplified. Neither can (a2 + b2) .
The answer is x = 3i and x = -3i. {Where i= √(-1)}An expression in the form a2 - b2 can be factored into (a - b)(a + b), but you have a2 + b2 so this factors into (a - bi)(a + bi). Check by multiplying the binomials: a2 + abi - abi - (bi)2 the [abi]'s cancel, and i2 = -1, so you have a2 + abi - abi - -b2 which is a2 + b2, so it checks out. In this case, a is x and b is 3.
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
A2 + B2 = C2 If C=8, then A2 + B2 = 64
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
(a - b + 2)(a + b + 2)