One plus cosecant squared x is equal to cotangent squared x.
secant of (A) = cosecant of (90- A) 'A' here is 80 degrees.
No.
The formula for "Take off" 45degrees elbow: 1.) For Metric: N.P.S. x 5/8 2.) For Imperial: N.P.S. x .625 Formula for travel of 45 degrees: Run x Cosecant 45degrees = Run x 1.4142 =
They are: 90 degrees, 45 degrees and 45 degrees
One plus cosecant squared x is equal to cotangent squared x.
1 + cot2x = csc2x
secant of (A) = cosecant of (90- A) 'A' here is 80 degrees.
1.624
No.
Approx 2.6131
Cosecant(115 deg) = 1/sine(115 deg) = 1/0.9063 = 1.1034
Hypotenuse = sqrt(side1 squared + side2 squared) and since the angles (other than the 90 degrees) are 45 degrees each, the side1 and side2 are equal, so Hypotenuse = sqrt((2 x side1) squared) = sqrt(4 x side1 squared) which is 2 x sqrt(side1 squared)
yes 1 + cot x^2 = csc x^2
Cosec(105 deg) = 1.0353
Assuming that "secany" is meant to be secant, the answer is cosecant.
The formula for "Take off" 45degrees elbow: 1.) For Metric: N.P.S. x 5/8 2.) For Imperial: N.P.S. x .625 Formula for travel of 45 degrees: Run x Cosecant 45degrees = Run x 1.4142 =