-3/-45
Work output divided by Work input Times 100
Assuming by in you mean input and out you mean output. Input is the value that goes in while the output is the value you receive. Between these terms is a rule, called the nth term that will always work to help you find the input/output. For example. Our input is 2, and our output is 10 the rule here could be the input multiplied by 5 equals the output, or it can be something extremely difficult and unfathomable even to a banker...
The mechanical efficiency of this machine is 30 percent.
It is -7.
Work Output=Resistance X Distance
because output work is input work divided by two
you have to do: work (output) divided by work (input) = F x d (output) divided by F x d (input)
efficiency.
Output work divided by input work
That is called the efficiency.
Work output divided by Work input Times 100
Output power divided by input power, for a machine, is called the machine's efficiency. It need not be mechanical energy.
Output is always greater than input. The output is multiplied from input.
All machines lose some of the input force applied to them as a result of friction and other forces. The efficiency of a machine refers to how much of the input work is converted to output work by the machine. You can find the efficiency of a machine by dividing the output work by the input work. Because the output work will always be smaller than input work, efficiency will always fall somewhere between 0 and 1, with 1 being a machine that has as much output as input work (not possible in the real world) and 0 being a machine that is totally useless because none of the input work is converted to output work.
Work Input = Work Output + Work done in overcoming friction.Therefore Work Input > Work Output.
input force x input distance > output force x output distance -Novanet
Work Input- The work done on a machine as the input force acts through the input distance. Work Output - The work done by a machine as the output force acts through the output distance (What the machine does to the object (dependent on the force) to increase the output distance).