Top Answer

You can write that as 5 / (a + b), or as a fraction, with the 5 on top, and a + b at the bottom. The actual value of this expression will depend on the values of "a" and "b".

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1what i would do is a/b cause we dont need to think hard into it

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2.5

The expression which represents half the sum of five and a number b is (b+5)/2.

2.5

2.5

The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953

(a + b)/(xy)

b: 28

5a plus 2b

if you let b= amount of money then b/20 = 7

You add 2 fractions with the same denominator [c], so the sum is the sum of the numerators divided by the denominator: a/c + b/c = (a+b)/c

5(a+b)-7

It is: 5*(b+2) which is the same as 5b+10

(a+b)/2 - 10 a+b divided by 2 and then minus 10

Expressed as a formula, this would be equal to (x + 5)/15.

For example:c = a + b;(This calculates the sum of a + b, and assigns the result to variable c.)If you repeatedly want to add something to an accumulated sum:b = b + a;or better:b += a;For example:c = a + b;(This calculates the sum of a + b, and assigns the result to variable c.)If you repeatedly want to add something to an accumulated sum:b = b + a;or better:b += a;For example:c = a + b;(This calculates the sum of a + b, and assigns the result to variable c.)If you repeatedly want to add something to an accumulated sum:b = b + a;or better:b += a;For example:c = a + b;(This calculates the sum of a + b, and assigns the result to variable c.)If you repeatedly want to add something to an accumulated sum:b = b + a;or better:b += a;

It is the sum of the number which is then divided by 2.

int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }

Five divided by 9,421 is 0.0005307292219519,421 divided by five is 1,884.2

The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.

the sum of the elements divided by the number of elements is the average

a = 5;b = 10;c = a + b;System.out.println("The sum is " + c);a = 5;b = 10;c = a + b;System.out.println("The sum is " + c);a = 5;b = 10;c = a + b;System.out.println("The sum is " + c);a = 5;b = 10;c = a + b;System.out.println("The sum is " + c);

1.6

#include<stdio.h> main() { int a,b,sum; print f("enter two numbers"); scan f("%d%d",&a&b); sum=a+b print f(the sum of a and b is %d,sum); }

Five halves divided by five fourths = 2

The sum of b and 8 would be written b+8 or 8+b(commutative property of addition)