Just write this as lambda/4, or (1/4)lambda. You can't get a numerical value, unless you know the value of lambda.
Pi Lambda Theta was created in 1910.
The base value of this structure is 253 nm. There are 4 alkyl substituents which add a value of 20 (4x5 nm). So the lambda max of this structure is 273 nm.
(4 factorial divided by .4) minus (the square root of 4 divided by .4) or 44 divided by (the square root of 4 divided by .4)
2.5
0.3125 Punch in 5 divided by 4, then press enter. After that, punch in divided by 4.
The motto of Lambda Lambda Lambda is 'Follow the Twelve'.
Lambda Lambda Lambda was created on 2006-01-15.
Mass divided by linear displacement (length or distance) is density, often called linear density or lambda.
Lambda is equal to the speed of light (3.00 x 10^8) divided by the velocity of the wave.
answer: λ
Hertz Antenna is lambda by 2 antenna & marconi antenna is lambda by 4 antenna...
Lambda Upsilon Lambda was created on 1982-02-19.
They try to join the fraternity Lambda, Lambda, Lambda (the "Tri-Lams").
The motto of Lambda Upsilon Lambda is 'La Unidad Para Siempre'.
Typically most researchers will want Cronbach's alpha even those Guttman's lambda 4 is better. So to answer your question lambda 4 would be best for reliability but most people use Cronbach's alpha and is generally accepted.
Given some matrix A, an eigenvector of A is a vector that, when acted on by A, will result in a scalar multiple of itself, i.e. Ax=[lambda]x, where lambda is a real scalar multiple, called an eigenvalue, and x is the eigenvector described.To find x you will normally have to find lambda first, which means solving the "characteristic equation": det(A-[lambda]I)=0, where I is the identity matrix.The derivation of the "characteristic equation" is as follows:Rearrange the equation Ax=[lambda]x -> Ax-[lambda]x=0 -> (A-[lambda]I)x=0 and then use the property from linear algebra that says if (A-[lambda]x) has an inverse, then x=0. Since this is trivial, we must instead prove that (A-[lambda]x) does not have an inverse. Because the inverse of a matrix is equal to its transpose divided by its determinant, and because you can't divide by 0, a 0 valued determinant means that the inverse can't exist. This is why we must solve det(A-[lambda]I)=0 for lambda.Once we have found lambda, we can put it in the equation Ax=[lambda]x, and it's then just a simple matter of solving the resulting linear equations.
Wavelength = (wave speed) divided by (period)