m(m - 6) = 91
m(m) + m(-6) = 91
m2 - 6m = 91 subtract 91 from both sides
m2 - 6m - 91 = 0 since -91 = (-13)(7) and -13 + 7 = -6, then
(m + 7)(m - 13) = 0
m + 7 = 0 or m - 13 = 0
m = -7 or m = 13
7a=2(-10)........................................answer is 20/7
(10-4/2)x3=24
You have to switch the sign of all terms within the parentheses. For example, -(a - b + c - d) becomes -a + b - c + d
You would need to know what a is equal to in order to calculate this equation.
It is a linear equation in two variables
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
7a=2(-10)........................................answer is 20/7
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
its a math problem
(x+8)(x-1)=0 x+8=0 x=-8 x-1=0 x=1 Therefore, the zeroes are -8 and 1.
The only number in that whole string of words whose value you don't already know, and can change from one minute to the next, is 'x'.
If you're talking about (K-0)=1, then the answer is most definitely 1.
13/21 - 7/21 = 6/21 Sorry, DJ, 4 over 7 = 12/21 so answer is 5/21
75r^2-48 You can take out 3.So... 3(25r^2-16) 3-parenthesis-25r squared-minus-16-parenthesis (:
To solve (184 + 243 + 808) - (109 + 72 + 84) evaluate the parentheses first: (184 + 243 + 808) - (109 + 72 + 84) = 1235 - 265 = 970
(10-4/2)x3=24
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.