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It is m7n-7.
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10y ago
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Q: What is m over n to the power of seven?
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How do you solve M to the power of 4 times N to the power of 5 minus M to the power of 20 times N to the power of 21 m4 n5 - m20n21?

m^4 n^5 - m^20 n^21


How do you solve a to the power of m times a to the power of n?

am * an = am+n


What are m and n when 4 over n times 9 times 2 over 9 whole thing powered n minus 2 times x power 6 minus 2n equals m over x power 2?

[(4/n)(9)(2/9)]^n -2x^6 - 2n=m/x^2 (8/n)^2 - 2x^6 -2n=m/x^2 (64x^2)/n^2 -2x^8 -2nx^2=m Now we know what m equals. I've got to go now. Sorry!


X over m minus y over n equals to 1 what is m?

m = xn/(n + y)


Program to find n raise to the power m?

P = 1 For K = 1 to M . P = P * N Next K PRINT "N raised to the power of M is "; P


The power required to exert 1 N force over a distance of 1 m in 1 second is?

1 Watt


What is the answer to -2m to the fourth power times n to the 6thpower to the 2nd power?

The question is open to multiple interpretations but I think you mean [(-2m)^4] x (n^6)^2 = [(-2)^4](m^4)(n^12) = 16(m^4)(n^12) or 16 times m to the 4th power times n to the 12th power.


What is M to the fourth power Times n to the fourth power?

m4n4


What is the power of a machine that does 1800 n-m of work per minute?

1 Watt = 1 N-m/sec 1800 N-m/sec = 1800 Watts


How do you make x the subject of m equals n plus (x over p)?

If: m = n+x/p then x = p(m-n)


What are some seven letter words with 1st letter M and 5th letter N and 7th letter N?

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern M---N-N. That is, seven letter words with 1st letter M and 5th letter N and 7th letter N. In alphabetical order, they are: meconin melanin


How do you write 1 as a power in three different ways and why?

For the purposes of this answer we will use the convention that x^n means xⁿ Any non-zero number to the zero power is 1 we get this from the idea that (x^n)(x^m) is x^(n+m) if n=-m, then n+m = 0 and x^ m is 1/(x^n) and (x^n)(x^m) (x^n)/(x^n)=1 so x^0 = 1 1 raised to any positive power is 1 1 raised to any negative power is 1 We can thus represent 1 as x^0 = 1 1^n = 1 1 ^(-n) = 1 (where n>0 Note that n need not be an integer since all roots of 1 are also 1)