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There are two square roots of i: (-1/square root 2)(1+i) and (1/square root 2)(1+i)

so these are i to the one half power. Now to find -i to the one half power, multiply either of these by i, since i2 is -1.

So (-i/square root 2)(1+i) and (i/square root 2)(1+i) are the square roots of -i.

Verify this by direct multiplication.

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โˆ™ 2009-05-31 06:43:26
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A polynomial of degree zero is a constant term

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A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What is negative i raised to the one half power?
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