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Q: What number divided by 5 gives remainder 3 and divided by 7 gives remainder 2?

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23 is an odd number between 10 and 30 that gives a remainder of 2 when divided by 7.

3

172

3 divided by 2 goes once, remainder one.

59

29

3 divided by 2 gives 1r1

58

57

No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11

17

27

3 divided by 2 has a remainder of 1. Which is 1 less than 2.

It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

169 is the smallest such number.

24

MOD (or modulus) gives the remainder when the first number is divided by the second. The remainder of 16 divided by 2 is 0, so 16 MOD 2 = 0.

16 \;p

It is an Odd number. Even numbers are those which have no remainder when divided by 2.

solve it with a calculater

Any number that can be divided by 2 and leave no remainder - for example, 2, 4, 6, 8, 10, is an even number.

Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1

179 works until divided by 7 the remainder is 6. 2519 works till 10....