answersLogoWhite

0


Best Answer

If you toss a coin often enough the probability is 1.

The probability of 9 H in the first 9 tosses is (1/2)9 = 1/512

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is probability of throwing 9 heads in a row?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

If you flip a coin and get 9 heads in a row what is the probability of getting heads on the next flip?

50%.


When a coin is tossed 9 times in a row what is the probability that heads comes up 9 times?

It is (1/2)9 = 1/512


What is the probability of getting heads from a coin 9 times in a row?

If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)


What is the probablity that the sequence will be heads-heads-heads if you toss a coin 3 times?

the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.


What is probability of throwing either 7 or more than 10 with two dice?

It is 9/36 = 1/4


A coin is tossed 9 times. What is the probability of getting exactly 4 heads.... What is the probability of getting at most 2 heads?

The number of trials: n = 9, the number of success: r = 4. The probability of success: P(H) = 1/2, the probability of failure: P(T) = 1/2. P(exactly 4 heads in 9 tosses) = 9C4 x (1/2)^5 x (1/2)^4 = 126(1/2)^9 = 0.246 P(at most 2 heads) = P(none heads) + P( 1 head) + P(2 heads) = 9C0[(1/2)^9][(1/2)^0] + 9C1[(1/2)^8][(1/2)^1] + 9C2[(1/2)^7][(1/2)^2] = 1(1/2)^9 + 9(1/2)^9 + 36(1/2)^9 = (1 + 9 + 36)(1/2)^9 = 46(1/2)^9 = 0.09


What is the probability of throwing a 3 or 6 if you role two dice at once?

In this case, you should first calculate the probability of NOT rolling either a 3 or a 6. For one die, this probability is 4/6 = 2/3. For two dice, this probability is 2/3 x 2/3 = 4/9. Therefore, the probability that you DO get a 3 or a 6 is 1 - 4/9 = 5/9.


Fair coin is tossed 11 times What is the probability that a Exactly 9 heads appear b At least two heads appear c At most 8 heads appear?

Prob(Exactly 9 Heads) = 0.0269 Prob(At least 2 Heads) = 0.0327 Prob(At most 8 Heads) = 0.9673


What is the probability of tossing a coin 9 times and getting at least one tail?

The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%


A fair coin is tossed 9 times What is the probability that At least two heads appear?

well, it will have 6 times of the greater chance.


A group of 5 women and 4 men are placed at random in 9 chairs in a row what is the probability that the result is an alternate seating arrangement?

(4!*5!)/9! = .0079


10 coins are tossed once .The probalilty of getting exactly eight heads is?

The probability of getting exactly eight heads when tossing 10 coins once can be found using the binomial probability formula. Assuming a fair coin, the probability of getting a heads is 1/2. Plugging in the numbers, the probability of getting exactly eight heads is (10 choose 8) * (1/2)^8 * (1/2)^2 = 45/1024, which is approximately 0.04395.