4 x2
36
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
7 minus the product of v and 3
rad 12 - 3 rad 3rad 12 = rad(4*3) = rad (4) * rad(3) = 2 rad 32 rad 3 - 3 rad 3= - rad 3
5
36
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
2-(3+p)
A Huge ASS
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
7 minus the product of v and 3
15
5
rad 12 - 3 rad 3rad 12 = rad(4*3) = rad (4) * rad(3) = 2 rad 32 rad 3 - 3 rad 3= - rad 3
1