Wiki User
∙ 2011-03-10 15:12:55What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4?
a14= a + 13d
= 100 + 13(-4)
= 48
Wiki User
∙ 2011-03-10 15:12:55It is a + 8d where a is the first term and d is the common difference.
16
6
From any term after the first, subtract the preceding term.
6
A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.
29
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
You take the difference between the second and first numbers.Then take the difference between the third and second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Take the difference between the fourth and third second numbers. If that difference is not the same then it is not an arithmetic sequence, otherwise it could be.Keep checking until you think the differences are all the same.That being the case it is an arithmetic sequence.If you have a position to value rule that is linear then it is an arithmetic sequence.
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
6
It is an Arithmetic Progression with a constant difference of 11 and first term 15.