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What is the 23rd term of the arithmetic sequence where a1 equals 8 and a9 equals 48?
Wiki User
∙ 11y ago
a1 = 8
a9 = 48
so 8*d = 40 so that d = 5
And so
a23 = 8 + 5*23 = 8 + 115 = 123
Wiki User
∙ 11y ago
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