The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
-1
Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.
the (n-1)th term plus the (n-2)th term.
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
82
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
The nth term of the sequence is 3n - 2.
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
20th term = 20*(20+1)/2
-1
Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.Triangular numbers are numbers in the sequence 1, 1+2, 1+2+3, 1+2+3+4. This sequence can be represented by triangles as follows: (very crude figure with an even cruder browser!)xxxxxxxxxxxxxxxxxxxxand so on.The nth term of this sequence is n*(n+1)/2.
the (n-1)th term plus the (n-2)th term.
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
The sequence S = 2, 2, 4, 6, 10, 16, 26, ... is the Fibonacci sequence multiplied by 2. Like the Fibonacci sequence, each term is found by adding the two previous terms, so Sn = Sn-1 + Sn-2.
The sum of an arithmetical sequence whose nth term is U(n) = a + (n-1)*d is S(n) = 1/2*n*[2a + (n-1)d] or 1/2*n(a + l) where l is the last term in the sequence.