260ef3
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
The LCM is 6b2c3
18a3bc
The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
LCM is 20, which is the multiple of the highest power of prime factors in the given numbers (22 x 5).The LCM is 20.
LCM(5y3, 25y6) = 25y6
The answer is 16x3
80a^3
The LCM is 72. The third LCM is 216.
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
The LCM is 42a2b2.
The LCM is 6b2c3
Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
11200
3
21
Since 20x7z2 is a multiple of 4x5z2, it is automatically the LCM.