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It is k*3x where k is an integer such that 10/(3x) < k < y/(3x)

Q: What is the Multiple of 3 and x is between 10 and Y?

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10-y=2y+3 10-3=2y+y 7=3y 7/3=y

The answer is y+3-3=7+3 y=10.

-13

X - Y = 10 X + Y = 4 -------------------+ ( add them ) 2X = 14 X = 7 ----------find Y in one of the equations; top looks good 7 - Y = 10 - Y = 3 Y = - 3 ---------------check both equations for consistency 7 - (- 3) = 10 7 + 3 = 10 10 = 10 ------------checks in top 7 + (- 3) = 4 7 - 3 = 4 4 = 4 ------------checks and is consistent (7, - 3) ( the answer )

y = xz where x = 3, z = 10 y = 3 x 10 = 30

Related questions

10-y=2y+3 10-3=2y+y 7=3y 7/3=y

3

The answer is y+3-3=7+3 y=10.

-13

X - Y = 10 X + Y = 4 -------------------+ ( add them ) 2X = 14 X = 7 ----------find Y in one of the equations; top looks good 7 - Y = 10 - Y = 3 Y = - 3 ---------------check both equations for consistency 7 - (- 3) = 10 7 + 3 = 10 10 = 10 ------------checks in top 7 + (- 3) = 4 7 - 3 = 4 4 = 4 ------------checks and is consistent (7, - 3) ( the answer )

y = xz where x = 3, z = 10 y = 3 x 10 = 30

Assuming that your question is x - y^3 Then you would do the following: x = -10 y = -3 -10 - (-3)^3 -10 - (-27) -10 + 27 = 17

2*(10^y + 11) = 4 - 5*(1 - 10^y) 2*10^y + 22 = 4 - 5 + 5*10^y 23 = 5*10^y - 2*10^y = 3*10^y Therefore 10^y = 23/3 and so y = log(23/3) = 0.885

If 4*y + 10 = 22Then 4*y = 12 (because 22 -10 = 12)Then y = 3 (because 4*3 =12)

It is: (-10)+(-3)+4 = -9

3 + Y where Y = 7 Substitute 7 for Y (because Y = 7) so: 3 + 7 = 10.

cross multiply 3/6=y/10 30=6y y=5