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Q: What is the Second derivative of natural logarithm of square root of X?

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3/(4*square root(x)) ....Mukesh

the derivative is 0. the derivative of a constant is always 0.

The derivative of sqrt(2) is zero.

The square root of any number which is not a perfect square;The cube root of any number which is not a perfect cube;Pi, the circular constant.e, the natural logarithm base number.

-1

The square root of x = x to the power of a half

Take the logarithm of 500, half it, then take the antilog.

Take its logarithm, divide that by 2 and take the antilog of your answer....

Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.

It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))

3

The derivative of ANY constant expression - one that doesn't depend on variables - is zero.

There are an infinite number of irrational numbers. Here are some: e (the base for natural logarithms), pi, sqrt(2), sqrt(3), sqrt(5), square root of any number that is not a perfect square: perfect squares are 12 22 32 42 52 etc. which equals 1 4 9 16 25 ..... natural logarithm of any rational number (greater than zero) will be irrational. but not 1, since ln(1) = 0, which is not irrational. Note the logarithm of a negative number is a complex number, and the logarithm of zero is negative infinity.

the product rule is included in calculus part.Product Rule : Use the product rule to find the derivative of the product of two functions--the first function times the derivative of the second, plus the second function times the derivative of the first. The product rule is related to the quotient rule, which gives the derivative of the quotient of two functions, and the chain rule, which gives the derivative of the composite of two functionsif you need more explanation, i want you to follow the related link that explains the concept clearly.

The derivative, with respect to x, is -x/sqrt(1-x2)

The derivative of any constant - any expression that does not involve the independent variable - is zero.

The simplest way to do it is to use Logarithms, from a book of Logarithmic Tables and Anti-logarithms. You simply look up the Logarithm of your quantity, then divide that quantity by 2 , and then look up its Anti-logarithm. that will give you the answer.

There is nothing to solve because there is no = sign.

sqrt(X) is also X^1/2 use power rule 1/2X^-1/2 ( first derivative ) -1/4X^-3/2 ( second derivative ) and so on

You should take the DERIVATIVE of the number or equation

Usually at the minimum or maximum of a function, one of the following conditions arises:The derivative is zero.The derivative is undefined.The point is at the end-points of the domain that is being considered (or of the naturally-defined domain, for example, zero for the square root).This will give you "candidate points"; to find out whether each of these candidate points actually is a maximum or a minimum, additional analysis is required. For example, if the second derivative is positive, you have a minimum, if the second derivative is negative, you have a maximum - but if it is zero, it may be a maximum, a minimum, or neither.

to get the logarythm of a number you must first find the square root of the number and then times it by the original number

Derivative with respect to 'x' of (5x)1/2 = (1/2) (5x)-1/2 (5) = 2.5/sqrt(5x)

1: Calculate the square root, then calculate its square root; OR 2: Take the logarithm of the number, divide it by 4 then take the antilog.

No - a natural number is a whole number. Therefore, the square root of 49 is a natural number, but the square root of 50 is not.