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What is the acceleration of a car that maintains a constant velocity of 100km per h for 10 seconds?
Wiki User
∙ 13y ago
Acceleration is the time rate of change of velocity. If velocity is constant, then
acceleration is zero.
Note:
"100 km per h for 10 seconds" is a constant speed, but not necessarily a constant
velocity, since we're told nothing about the direction. If the car moves in a perfectly
straight line during those 10 seconds, then its velocity is constant. If it makes a curve,
then its velocity is not constant even though its speed is, and there is acceleration.
Wiki User
∙ 13y ago
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What is the acceleration of a car that maintains a constant velocity of 100 kilometers per hour for 10 seconds?
The answer is very simple. The words "constant velocity" are the definition of zero acceleration.
How does constant velocity differ from constant acceleration?
Constant velocity is a measure of distance traveled per unit of time at a uniform speed, such as miles per hour or feet per second. Constant acceleration is a measure of a continuing increase in velocity per unit of time, as when a car speeds up from 30 miles per hour to 40 miles per hour in 5 seconds, then from 40 miles per hour to 50 miles per hour during the next 5 seconds. It will then have had a constant acceleration of 10 miles per hour per 5 seconds.
How do you work out velocity when given acceleration and time?
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
Acceleration is defined as a change in velocity over time if a runner increases velocity from 2 m s to 4 m s over a period of 20 seconds what is the acceleration?
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
What is the average acceleration between 0 seconds and 4 seconds?
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
What is the acceleration of a car that maintains a constant velocity of 100 kilometers per hour for 10 seconds?
The answer is very simple. The words "constant velocity" are the definition of zero acceleration.
Can bodies with different velocities have same acceleration?
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.
How does constant velocity differ from constant acceleration?
Constant velocity is a measure of distance traveled per unit of time at a uniform speed, such as miles per hour or feet per second. Constant acceleration is a measure of a continuing increase in velocity per unit of time, as when a car speeds up from 30 miles per hour to 40 miles per hour in 5 seconds, then from 40 miles per hour to 50 miles per hour during the next 5 seconds. It will then have had a constant acceleration of 10 miles per hour per 5 seconds.
If you are going 50miles hours for 30 seconds what is the acceletation?
Acceleration is the rate of change in velocity (speed) Thus if your speed is constant (50 miles per hour) your acceleration is zero
What is the velocity of car if it is moving with constant acceleration?
I'm assuming you are not talking about constant acceleration, which in itself iscontinuous. If you are talking about constant (meaning it's just a number, and not a function itself) acceleration, than just use the formula:v = i + at, wherev = velocity, i = initial velocity, a = acceleration, and t = timeOtherwise, you need to have some calculus knowledge. A velocity function is just the antiderivative (integral) of an acceleration function.Say, acceleration was given as:a = 2ttake the integral of thatv =∫ 2t dt = (2/2)t2+c =t2+cIn this case, the c is the initial velocity.Example:An object moves with an acceleration determined by a=t+3 (in m/s^2). Find the velocity of the object after 10 seconds have passed, given that the object has an initial velocity of 2 m/s.a = t + 3v =∫( t + 3) dt = (1/2)t2 + 3t + c, with c being initial velocityv(10 seconds) = (1/2)(10)2 + 3(10) + (2) = 82 m/s
How do you work out velocity when given acceleration and time?
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
Acceleration is defined as a change in velocity over time if a runner increases velocity from 2 m s to 4 m s over a period of 20 seconds what is the acceleration?
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
When acceleration occurs?
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Can a body have constant acceleration and zero velocity?
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
An object with constant velocity has positive acceleration?
Answer This occurs when an object istraveling in one direction but has an acceleration in the opposite direction, which means it is decreasing in speed. For a given period of time, the speed has decreased. Acceleration is the change of velocity per second. T1 = 5 seconds V1 = 100mph T2 = 10 seconds V2= 50 mph Acceleration = (V2 - V1 ) / (T2 - T1) = (50-100)/(10-5) = -10 ft/sec/sec Positive(+) acceleration means an object will be going faster over an interval of time.
What is the average acceleration between 0 seconds and 4 seconds?
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
If a car goes in 6.8 seconds how do you figure out the acceleration?
Acceleration= distance / velocity squared
