Study guides

Q: Sum of squares of first 1000 positive odd integers?

Write your answer...

Submit

Related questions

The sum of the positive integers from 1,000 to 1,100 inclusive is: 106,050

666 integers.

750

1,2,3,4,5,6,7,8,9,10 all the way thru 1000.

Using Gauss's method, 1+2+3...1000= 500x1001=500500 Answer:500500

Infinitely many, since every positive number is a square of some other number. However, there are 21 perfect squares (SQUARES OF INTEGERS). From 112 to 312, inclusive.

The sum of the first 1,000 integers (whole numbers) is 499,500.

2, 4, 6, 8, ... continue adding 2 at a time, up to 2000.

There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.

1 and 2 are the only positive integers.

There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.

52

405

There are 544 positive integers less than 1,000 that are either divisible by two or by 11.

There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11

332

from 1000 to 9999, ie 9999 - 999 = 9000

130 numbers

334 of them.

10*9*8=720

There are 870 such numbers.

There is only 1, the number 54.

To get a list of the squares of the first 1000 numbers we can do:> [n^2 | n sum [n^2 | n

9000 integers.

There are 30 such integers.