the answer is 8,640 the total interior angles of pentacontagon.
The sum of the interior angles of a polygon can be found using the formula: (n-2) × 180° Therefore, the interior angles of a pentacontagon; a fifty-sided polygon, will add up to: (50-2) × 180° (48) × 180° 8640°
A Pentacontagon has 50 sides.
The sum of one angle is simply the measure of that angle.
A pentacontagon has 50 vertices (not vertices's!).
angle sum of a parallelogram
the angle sum of a pentagon is 540.
Now, a 50-gon (the correct term is a pentacontagon, but that takes too long to type) has 50 sides. The equation for the interior angle of a regular polygon (we're talking about a regular 50-gon, right?) is [(n-1)*180]\n where n is the number of sides the polygon has. So in this case, the sum of the interior angles is 8820, and the measure of one angle is 176.4 degrees.
An angle sum is the sum (in degrees) of the particular angles you are measuring.
It means the sum of the angle measurements.
It is the measure of the angle!
The sum of an angle is a poitless concept: it is simply the measure of the angle and does not add any information.The sum of more than one angles refers to the sum of their values.