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Here, there is no symbol between the 3s.
2 X 33X -4?
That'd be...
-264.
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
3x+4 = 2x-3 3x-2x = -3-4 x = -7
2x+3=3x-3 2x-3x=-3-3 -x=-6 x=6
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
3x + 4 = 2x - 3 Subtract 2x from both sides: x + 4 = - 3 Subtract 4 from both sides: x = -7
2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
x -3x + 4 = 3 - 9-2x + 4 = -6-2x = -102x = 10x = 5
-6x2 + 17x -12. To get the solution, we set up the formula as follows: (2x - 3) * (4 - 3x) Then we multiply each of the components as follows: (2x * 4) + (2x * -3x) + (-3 * 4) + (-3 * -3x) Then we simplify as follows: 8x + -6x2 + -12 + 9x -6x2 + 17x + -12 -6x2 + 17x -12
3x - 2x + 4 = 0 3x - 2x = -4 x = -4
3x+56 = 2x+4 3x-2x = 4-56 x = -52
2x
2x