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It depends on what you are looking for regarding y=50-5t. Try to include more details in the future.

The y intercept is y=50
The x-intercept is:t=10


There are no critical points, so there are no maximum or minimum functions.


The function is linear, with a slope of -5, therefore y`= -5


The integral is:


∫ 50-5t dt =

50t - 5/2t2 + C

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12y ago

What else can I help you with?