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Interior + Exterior = 180 and Interior = 5*Exterior

So interior = 150 degrees and exterior = 30 degrees.

Nothing more may be said unless it is known that the polygon is regular.

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โˆ™ 2011-10-10 12:29:51
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Q: What is the answer of the polygon interior angle is five times the size of exterior?
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How many sides does the polygon have if it has an interior angle which is 3 times the exterior angle?

Providing that it is a regular polygon it will have 8 sides.


What regular polygon has interior angle 177?

If interior angles are 177o then exterior angles are 3o. Exterior angle times number of sides is always 360 so the polygon has 120 sides.


How many sides does an equiangular polygon have if the measure of an angle of the polygon exceeds four times the measure of one of it's exterior angles by 30?

Interior angle + Exterior angle = 180 So Interior angle = 180 - Exterior angle Interior angle = 4*Exterior angle + 30 Substitute for Interior angle: 180 - Exterior angle = 4*Exterior angle + 30 Collect like terms: 150 = 5*Exterior angle Divide by 5: Exterior angle = 30 deg Therefore number of sides = 360/30 = 12


How many sides does the regular polygon have if each interior angle measure is four times the measure of each exterior angle measure?

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Which regular polygon's interior angles is three times that of its exterior angles?

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How many sides has a regular polygon whose interior angle is 11 times its exterior angles?

The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nThe measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nIf the interior angle is 11 times the exterior angle, then:180 (n-2)/n = 11 x 360/nthen: 180 n - 360 = 11 x 360, or180 n = 12 x 360that its solution gives n = 24Accordingly, the answer is that the number of sides of this polygon is 24


How can you prove that the sum of exterior angles of a polygon is 360 degrees?

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Calculate number of sides of a regular polygon has if an interior angle is five times the size of an exterior angle?

Suppose the interior angle is x degrees. Then the exterior angle is 180 - x degrees. x = 5*(180-x) = 900 - 5x So 6x = 900 so that x = 150 degrees. So exterior angle = 30 degrees. If the polygon has n sides (and n angles) the sum of its exterior angles is 30*n But the exterior angles of a polygon add to 360 degrees So 30*n = 360 so that n = 12. ANSWER: 12 sides.


How do you find the exterior angle of a polygon?

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What is the number of sides in a regular polygon in which the measure of an interior angle is seventeen times the measure of an exterior angle?

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What is the number of sides of a regular polygon in which the measure of an interior angle is seventeen times the measure of an exterior angle?

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What polygon has the sum of the interior angles equal to two times the sum of the exterior angles?

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