1
-2z to the second power is 4*z^2. If z = -3, then this is 36.
3xz
-2z + 3
2z-28 = -26
2z+17=21 subtract 17 from both sides. 2z=4 divide both sides by 2 z=2
Mid-point: (3z+z)/2, (2z+8z)/2 = (2z, 5z) Slope: (8z-2z)/(3z-z) = 6z/2z = 3 Perpendicular slope: -1/3 Equation: y -5z = -1/3(x -2z) => y = -1/3x+2z/3+5z => y = -1/3x+17z/3 General form of the bisector equation: x+3y-17z = 0
The GCF is 2z
2z(5z - 1)(25z^2 + 5z + 1)
(-3) x (-2z - 7) = 6z + 21 = 3 (2z + 7)
3xz
-2z + 3
2z-28 = -26
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
16(2z-3)
You cannot solve this statment as there is nothing to equate to it. However, it will factor. 9 - 4z^2 First we note that both '9' and '4' are squared numbers. 9 = 3^(2) & 4 = 2^(2) So we can re-write the statement as 3^(2) - (2z)^(2) Note that it now has two squared terms with a negative between them . This will factor to 3^(2) = (2z)^2 = ( 3 - 2z_)(3 + 2z) NOTE the different signs. NB Two squared terms with a positive(+) between them will NOT factor.
(1) y2-2zy-2y-2z-3 = y2 -2y (z+1) - (2z+3) Delta = [-(z+1)]2 - (- (2z+3)) = z2+2z+1+2z+3= z2+2z+4 = (z+2)2 (If used the reduced form as b=-2(z+1) is even, b'=-(z+1) and delta=b'2-ac) y=(z+1) ± (z+2) so y = 2z+3 or y =-1 So the (1) can be written (y-2z-3)(y+1)
2z+9.75-7z=-5.15
2(z-2)(z-5)